7m^2-45m+18=0

Solution for 7m^2-45m+18=0 equation:

7m^2-45m+18=0

a = 7; b = -45; c = +18;
Δ = b2-4ac
Δ = -452-4·7·18
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-39}{2*7}=\frac{6}{14}
=3/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+39}{2*7}=\frac{84}{14}
=6
$